pythontkinter如何判斷Entry文本框中是否有小數(shù)點,？

訪客2025-02-10 09:27:331

代碼如下：from tkinter import *def main():root = Tk()root.title('calculator')a = Variable()e1 = Entry(root,width=28,bd=0,textvariable=a)e1.place(x=0,y=0)def b(): c = e1.get()+str(1) a.set(c)def b1(): c = e1.get()+str(2) a.set(c)def b2(): c = e1.get()+str(3) a.set(c)def b3(): c = e1.get() + str(4) a.set(c)def b4(): c = e1.get() + str(5) a.set(c)def b5(): c = e1.get() + str(6) a.set(c)def b6(): c = e1.get() + str(7) a.set(c)def b7(): c = e1.get() + str(8) a.set(c)def b8(): c = e1.get() + str(9) a.set(c)def b9(): c = e1.get()+str(0) a.set(c) def bd(): c = e1.get() if c=='': c1 = c+str('0.') a.set(c1) else: pass Button(root,text='1',width=3,height=1,bd=1,command=b).place(x=0,y=80) Button(root,text='2',width=3,height=1,bd=1,command=b1).place(x=30,y=80) Button(root,text='3',width=3,height=1,bd=1,command=b2).place(x=60,y=80) Button(root,text='4',width=3,height=1,bd=1,command=b3).place(x=0,y=110) Button(root,text='5',width=3,height=1,bd=1,command=b4).place(x=30,y=110) Button(root,text='6',width=3,height=1,bd=1,command=b5).place(x=60,y=110) Button(root,text='7',width=3,height=1,bd=1,command=b6).place(x=0,y=140) Button(root,text='8',width=3,height=1,bd=1,command=b7).place(x=30,y=140) Button(root,text='9',width=3,height=1,bd=1,command=b8).place(x=60,y=140) Button(root,text='0',width=6,height=1,bd=1,command=b9).place(x=0,y=170) Button(root,text='.',width=3,height=1,bd=1,command=bd).place(x=60,y=170) mainloop()if __name__ == '__main__': main()可見我這是在編譯該計算器,，但是我在弄小數(shù)點的按鈕的時候遇到了困難，就是我無法判斷在按下'.'按鈕前Entry文本框中是否有其他小數(shù)點，怎么辦呢,？